I'm sucked back into this thread. I hate myself for responding.YugoRPK wrote:
H2O2 will release more oxygen than H20 for the first cycle but it is unstable and quickly reverts to good old dihydrogen monoxide.
Not that any of this will actually work ...It won't for the reasons listed by GNR . A faster flame front doesnt mean "better" combustion even if the hydrogen would accelerate the flame front. Hydrogen in the presence of oxygen burns SLOWER than a stoichiometric mix of aerosol gasoline and air. Engine efficiency can be increased by increasing the compression ratio using a fuel with a slower burning flame front to avoid detonation while maintaining even combustion pressures and then using a cam and drivetrain profile to take advantage of that increase in power in the range it is produced. For that reason and that reason only there is a possibility that it ...gulp...may actually have some merit although dyno testing is the only real way to determine that. I havent seen any of that. When I was building race engines I ran a LOT of engines on dynamometers and I know the BSFC number will tell you everything you need to know. There my be some change but I expect it will be negligible or within the statistical margin of error. That's with an engine dyno. Chassis dyno's are only useful if fuel metering equipment is installed and a manual or full lockup converter automatic transmission is used. Even OBD2 equipment only estimates fuel consumption and is not reliable in determining Brake Specific Fuel Consumption.
The above isn't really true since the whole mixture would be getting saturated with free electrons. That H2O2 would split into HHOO, just as H20 splits into HOH. I'd think this process could even be slightly more efficient since the that last "O" is already so willing to jump ship from regular hydrogen peroxide. Now its true that when the regular O jumps, it pairs up with another O and makes O2 - and I don't know if it can be split further once its a gas and free of electrolysis's influence. But it shouldn't matter because O2 burns fine on its own. Its a zero-sum game because the overall system to put that O in the H2O is still effort somewhere.